Tamaños de base de datos MySQL Workbench

12

Estoy tratando de encontrar el tamaño total en el disco duro que utilizan todas mis bases de datos MySQL Workbench.

¿Alguien sabe de una manera fácil de resolver esto?

Por lo menos, ¿la ubicación predeterminada que usa mysql / workbench para guardar los datos sin procesar en una máquina Windows?

¡Gracias por adelantado! Quintis

mysql  windows  mysql-workbench  database-size 
— Quintis555
fuente

Respuestas:

12

Tengo algunas consultas que puede ejecutar contra el INFORMATION_SCHEMA

Ejecute esto para obtener el uso total de datos e índices de MySQL por el motor de almacenamiento

SELECT IFNULL(B.engine,'Total') "Storage Engine",
CONCAT(LPAD(REPLACE(FORMAT(B.DSize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') "Data Size", CONCAT(LPAD(REPLACE(
FORMAT(B.ISize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') "Index Size", CONCAT(LPAD(REPLACE(
FORMAT(B.TSize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') "Table Size" FROM
(SELECT engine,SUM(data_length) DSize,SUM(index_length) ISize,
SUM(data_length+index_length) TSize FROM
information_schema.tables WHERE table_schema NOT IN
('mysql','information_schema','performance_schema') AND
engine IS NOT NULL GROUP BY engine WITH ROLLUP) B,
(SELECT 3 pw) A ORDER BY TSize;

Ejecute esto para obtener el uso total de datos e índices de MySQL por base de datos

SELECT DBName,CONCAT(LPAD(FORMAT(SDSize/POWER(1024,pw),3),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') "Data Size",CONCAT(LPAD(
FORMAT(SXSize/POWER(1024,pw),3),17,' '),' ',SUBSTR(' KMGTP',pw+1,1),'B') "Index Size",
CONCAT(LPAD(FORMAT(STSize/POWER(1024,pw),3),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') "Total Size" FROM
(SELECT IFNULL(DB,'All Databases') DBName,SUM(DSize) SDSize,SUM(XSize) SXSize,
SUM(TSize) STSize FROM (SELECT table_schema DB,data_length DSize,
index_length XSize,data_length+index_length TSize FROM information_schema.tables
WHERE table_schema NOT IN ('mysql','information_schema','performance_schema')) AAA
GROUP BY DB WITH ROLLUP) AA,(SELECT 3 pw) BB ORDER BY (SDSize+SXSize);

Ejecute esto para obtener el uso total de datos e índices de MySQL por base de datos y motor de almacenamiento

SELECT Statistic,DataSize "Data Size",IndexSize "Index Size",TableSize "Table Size"
FROM (SELECT IF(ISNULL(table_schema)=1,10,0) schema_score,
IF(ISNULL(engine)=1,10,0) engine_score,
IF(ISNULL(table_schema)=1,'ZZZZZZZZZZZZZZZZ',table_schema) schemaname,
IF(ISNULL(B.table_schema)+ISNULL(B.engine)=2,"Storage for All Databases",
IF(ISNULL(B.table_schema)+ISNULL(B.engine)=1,
CONCAT("Storage for ",B.table_schema),
CONCAT(B.engine," Tables for ",B.table_schema))) Statistic,
CONCAT(LPAD(REPLACE(FORMAT(B.DSize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') DataSize,CONCAT(LPAD(REPLACE(
FORMAT(B.ISize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') IndexSize,
CONCAT(LPAD(REPLACE(FORMAT(B.TSize/POWER(1024,pw),3),',',''),17,' '),' ',
SUBSTR(' KMGTP',pw+1,1),'B') TableSize FROM (SELECT table_schema,engine,
SUM(data_length) DSize,SUM(index_length) ISize,
SUM(data_length+index_length) TSize FROM information_schema.tables
WHERE table_schema NOT IN ('mysql','information_schema','performance_schema')
AND engine IS NOT NULL GROUP BY table_schema,engine WITH ROLLUP) B,
(SELECT 3 pw) A) AA ORDER BY schemaname,schema_score,engine_score;

CONSIDERACIÓN

En cada consulta, verá (SELECT 3 pw). El pw significa Power Of 1024 para mostrar los resultados.

  • (SELECT 0 pw) mostrará el informe en bytes
  • (SELECT 1 pw) mostrará el informe en KiloBytes
  • (SELECT 2 pw) mostrará el informe en MegaBytes
  • (SELECT 3 pw) mostrará el informe en GigaBytes
  • (SELECT 4 pw) mostrará el informe en TeraBytes
  • (SELECT 5 pw) mostrará el informe en PetaBytes (contácteme si ejecuta este)

Aquí hay una consulta de informe con un poco menos de formato:

SELECT IFNULL(db,'Total') "Database",
datsum / power(1024,pw) "Data Size",
ndxsum / power(1024,pw) "Index Size",
totsum / power(1024,pw) "Total"
FROM (SELECT db,SUM(dat) datsum,SUM(ndx) ndxsum,SUM(dat+ndx) totsum
FROM (SELECT table_schema db,data_length dat,index_length ndx
FROM information_schema.tables WHERE engine IS NOT NULL
AND table_schema NOT IN ('information_schema','mysql')) AA
GROUP BY db WITH ROLLUP) A,(SELECT 1 pw) B;

Darle una oportunidad !!!

ACTUALIZAR

Acabo de ejecutar la primera consulta como está en la base de datos de un cliente

mysql> SELECT IFNULL(B.engine,'Total') "Storage Engine",
    -> CONCAT(LPAD(REPLACE(FORMAT(B.DSize/POWER(1024,pw),3),',',''),17,' '),' ',
    -> SUBSTR(' KMGTP',pw+1,1),'B') "Data Size", CONCAT(LPAD(REPLACE(
    -> FORMAT(B.ISize/POWER(1024,pw),3),',',''),17,' '),' ',
    -> SUBSTR(' KMGTP',pw+1,1),'B') "Index Size", CONCAT(LPAD(REPLACE(
    -> FORMAT(B.TSize/POWER(1024,pw),3),',',''),17,' '),' ',
    -> SUBSTR(' KMGTP',pw+1,1),'B') "Table Size" FROM
    -> (SELECT engine,SUM(data_length) DSize,SUM(index_length) ISize,
    -> SUM(data_length+index_length) TSize FROM
    -> information_schema.tables WHERE table_schema NOT IN
    -> ('mysql','information_schema','performance_schema') AND
    -> engine IS NOT NULL GROUP BY engine WITH ROLLUP) B,
    -> (SELECT 3 pw) A ORDER BY TSize;
+----------------+----------------------+----------------------+----------------------+
| Storage Engine | Data Size            | Index Size           | Table Size           |
+----------------+----------------------+----------------------+----------------------+
| MyISAM         |             0.673 GB |             0.079 GB |             0.752 GB |
| InnoDB         |             4.227 GB |             2.436 GB |             6.663 GB |
| Total          |             4.900 GB |             2.515 GB |             7.415 GB |
+----------------+----------------------+----------------------+----------------------+
3 rows in set (0.79 sec)

mysql>

Funciona como es

ACTUALIZACIÓN 2015-01-16 14:46 EST

Aquí hay consultas para informar tamaños y computa las unidades de memoria sobre la marcha

Uso total de datos e índices de MySQL por motor de almacenamiento

SELECT IFNULL(ENGINE,'Total') "Storage Engine",
LPAD(CONCAT(FORMAT(DAT/POWER(1024,pw1),2),' ',
SUBSTR(units,pw1*2+1,2)),17,' ') "Data Size",
LPAD(CONCAT(FORMAT(NDX/POWER(1024,pw2),2),' ',
SUBSTR(units,pw2*2+1,2)),17,' ') "Index Size",
LPAD(CONCAT(FORMAT(TBL/POWER(1024,pw3),2),' ',
SUBSTR(units,pw3*2+1,2)),17,' ') "Total Size" FROM
(SELECT ENGINE,DAT,NDX,TBL,IF(px>4,4,px) pw1,
IF(py>4,4,py) pw2,IF(pz>4,4,pz) pw3 FROM
(SELECT *,FLOOR(LOG(IF(DAT=0,1,DAT))/LOG(1024)) px,
FLOOR(LOG(IF(NDX=0,1,NDX))/LOG(1024)) py,
FLOOR(LOG(IF(TBL=0,1,TBL))/LOG(1024)) pz
FROM (SELECT ENGINE,SUM(data_length) DAT,SUM(index_length) NDX,
SUM(data_length+index_length) TBL FROM (SELECT engine,data_length,index_length
FROM information_schema.tables WHERE table_schema NOT IN
('information_schema','performance_schema','mysql') AND ENGINE IS NOT NULL) AAA
GROUP BY ENGINE WITH ROLLUP) AAA ) AA) A,(SELECT ' BKBMBGBTB' units) B;

Uso total de datos e índices de MySQL por base de datos

SELECT IFNULL(DB,'Total') "Database",
LPAD(CONCAT(FORMAT(DAT/POWER(1024,pw1),2),' ',
SUBSTR(units,pw1*2+1,2)),17,' ') "Data Size",
LPAD(CONCAT(FORMAT(NDX/POWER(1024,pw2),2),' ',
SUBSTR(units,pw2*2+1,2)),17,' ') "Index Size",
LPAD(CONCAT(FORMAT(TBL/POWER(1024,pw3),2),' ',
SUBSTR(units,pw3*2+1,2)),17,' ') "Total Size"
FROM (SELECT DB,DAT,NDX,TBL,IF(px>4,4,px) pw1,
IF(py>4,4,py) pw2,IF(pz>4,4,pz) pw3 FROM
(SELECT *,FLOOR(LOG(IF(DAT=0,1,DAT))/LOG(1024)) px,
FLOOR(LOG(IF(NDX=0,1,NDX))/LOG(1024)) py,
FLOOR(LOG(IF(TBL=0,1,TBL))/LOG(1024)) pz
FROM (SELECT DB,SUM(data_length) DAT,SUM(index_length) NDX,
SUM(data_length+index_length) TBL FROM
(SELECT table_schema DB,data_length,index_length FROM information_schema.tables
WHERE table_schema NOT IN ('information_schema','performance_schema','mysql')
AND ENGINE IS NOT NULL) AAA GROUP BY DB WITH ROLLUP) AAA) AA) A,
(SELECT ' BKBMBGBTB' units) B;

Uso total de datos e índices MySQL por motor de base de datos / almacenamiento

SELECT IF(ISNULL(DB)+ISNULL(ENGINE)=2,'Database Total',
CONCAT(DB,' ',IFNULL(ENGINE,'Total'))) "Reported Statistic",
LPAD(CONCAT(FORMAT(DAT/POWER(1024,pw1),2),' ',
SUBSTR(units,pw1*2+1,2)),17,' ') "Data Size",
LPAD(CONCAT(FORMAT(NDX/POWER(1024,pw2),2),' ',
SUBSTR(units,pw2*2+1,2)),17,' ') "Index Size",
LPAD(CONCAT(FORMAT(TBL/POWER(1024,pw3),2),' ',
SUBSTR(units,pw3*2+1,2)),17,' ') "Total Size" FROM
(SELECT DB,ENGINE,DAT,NDX,TBL,
IF(px>4,4,px) pw1,IF(py>4,4,py) pw2,IF(pz>4,4,pz) pw3 FROM
(SELECT *,FLOOR(LOG(IF(DAT=0,1,DAT))/LOG(1024)) px,
FLOOR(LOG(IF(NDX=0,1,NDX))/LOG(1024)) py,
FLOOR(LOG(IF(TBL=0,1,TBL))/LOG(1024)) pz
FROM (SELECT DB,ENGINE,SUM(data_length) DAT,SUM(index_length) NDX,
SUM(data_length+index_length) TBL FROM (SELECT table_schema DB,ENGINE,
data_length,index_length FROM information_schema.tables WHERE table_schema NOT IN
('information_schema','performance_schema','mysql') AND ENGINE IS NOT NULL) AAA
GROUP BY DB,ENGINE WITH ROLLUP) AAA) AA) A,(SELECT ' BKBMBGBTB' units) B;
— RolandoMySQLDBA
fuente
1
He estado usando information_schema.partitions: ¿hay alguna diferencia por favor?
— gbn
@gbn: las consultas se segregan por engine, que no es una columna en information_schema.partitions. Aparte de eso, information_schema.partitions captura todas las tablas, incluso las no particionadas. Solo recuerde excluir information_schemay mysqlde las cláusulas WHERE que verifican table_schema.
— RolandoMySQLDBA 01 de
Tuve algunos errores con el código que proporcionó, pero no tengo la experiencia suficiente para saber cómo depurarlos. encontré algún otro código en línea SELECT table_schema, sum(data_length) / 1024 / 1024 "data", sum(index_length) / 1024 / 1024 "index", sum( data_length + index_length ) / 1024 / 1024 "total" FROM information_schema.TABLES GROUP BY table_schema;¿Parece que esto funcionará? Toda la consulta information_schema / table_schema es nueva para mí. (Si no puede decirlo, soy bastante nuevo en todo esto :) ¡Gracias!
— Quintis555
2
+1 se ha registrado para poder hacer +1 en esto. ¿Por qué esto no tiene más votos? ¡Gracias!
— Reactgular
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