Respuestas:
La monogamia no es para todos.
Basado en mi respuesta a Ejecutar impresiones al revés .
#define def main(){0?
#define print printf(
#define return 0)));}
def main():
print "Python",
print ", I love you much more than ",
print "C",
return
main();
Salida, cuando se ejecuta como C:
C, I love you much more than Python
Salida, cuando se ejecuta como Python:
Python , I love you much more than C
Versión bonita:
r=/c/g ,n='\n'
,m=/.\d+/g,[, ,'ca','8b',5,
'a10b',6,'ca3b', 13,'a4b',1,3,'c'
,'a1b',16,'a2b1',5,'cb35cb',35,'ca',
,'1b7 JS b',22,'ca2b',31,'ca3b',29,
,'ca',5,'b',25,'ca7b',2,1,'ca',9,
,'b','17ca',11,'b13ca',14,'b',
'7c','a1',7,'b1c'].join('').
replace(m, c=>(c[0]!='a'?
'\u2665':' ').repeat
(+c.substr(1))).
replace(r,
n);
Salida de consola:
♥♥♥♥♥ ♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥ ♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥ ♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥ JS ♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥♥♥♥♥♥♥
♥♥♥♥♥♥♥
♥
Versión anotada:
[
// Contains the instruction to draw the heart.
// * `a` is a space
// * `b` is a heart
// * `c` is a line break
//
// `a` and `b` instructions are followed by an integer
// telling how many times the character should be printed.
//
// Abuse JS arrays to split the string in smaller parts.
,,'ca','8b',5,'a10b',6,'ca3b',13,'4b13ca1b16a2b1cb35cb35ca1b7'
// This is the text we want to display.
,' JS '
// Other instructions to draw the heart.
// This part isn't splitted for readability purpose.
,'bca2bca3b29ca5b25ca7b21ca9b17ca11b13ca14b7ca17b1c'
]
// Join every substring.
.join('')
// Process instructions.
.replace(
// Match all `a` and `b` instructions.
/.\d+/g,
c => (
// Fetch the right character.
c[0] != 'a'
? '\u2665' // `b` Heart
: ' ' // `a` Space
)
// Repeat the character.
.repeat(
// Extract the number from the instruction.
+c.substr(1)
)
)
// Replace `c` by a line break.
.replace(/c/g,'\n');
public static final int px = 25;
public static final int rectRad = 3;
PFont font;
public boolean[][] used;
public int[] heart = {
65, 66, 67, 72, 73, 74,
84, 85, 86, 87, 88, 91, 92, 93, 94, 95,
103,104,105,106,107,108,109,110,111,112,113,114,115,116,
122,123,124,125,126,127,128,129,130,131,132,133,134,135,136,137,
142,143,144,145,146,147,148,149,150,151,152,153,154,155,156,157,
162,163,164,165,166,167,168,169,170,171,172,173,174,175,176,177,
183,184,185,186,187,188,189,190,191,192,193,194,195,196,
204,205,206,207,208,209,210,211,212,213,214,215,
224,225,226,227,228,229,230,231,232,233,234,235,
245,246,247,248,249,250,251,252,253,254,
266,267,268,269,270,271,272,273,
287,288,289,290,291,292,
308,309,310,311,
329,330
};
void setup() {
size(500, 500);
background(255);
stroke(127+64);
strokeWeight(1.75);
//font=loadFont("Font1.vlw");
font=createFont("Purisa",28);
textFont(font,28);
frameRate(50);
used = new boolean[width/px][height/px]; // initialised to false by default
}
void draw() {
int i, j;
int drawingframes = width * height / px / px;
int textframesdelay = (int)(500 * frameRate / 1000);
do {
i=(int)random(0, width / px);
j=(int)random(0, height / px);
} while(used[i][j] && frameCount <= drawingframes);
used[i][j] = true;
if(frameCount > drawingframes + textframesdelay) {
noLoop();
return;
} else if(frameCount == drawingframes + textframesdelay) {
fill(63 + 32);
text("Dear Processing,", 10, 50);
text("Happy Valentine's Day!", 80, 200);
text("Love,\nAce", 10, 430);
return;
} else if(frameCount > drawingframes) {
return; // effectively creating a small delay after drawing the tiles
// and before writing the text
}
int R = (int)random(64, 255 - 64);
int G = (int)random(128, 255);
int B = (int)random(128, 255);
int alpha = (int)random(55, 85);
int hash = j * width / px + i;
if(java.util.Arrays.binarySearch(heart,hash)>=0) {
//if(heart.indexOf(hash) >= 0) {
R = (int)random(128 + 64, 255);
G = (int)random(0, 63);
B = (int)random(0, 63);
alpha = (int)random(70, 100);
}
fill(R, G, B, alpha);
rect(i * px, j * px, px, px, rectRad, rectRad, rectRad, rectRad);
}
Véalo correr en línea aquí .
Captura de pantalla de una salida posible:
¿Por qué complicarse demasiado, cuando puedes hacer lo más simple que funciona?
Programa:
I ♥ PHP!
Salida:
I ♥ PHP!
GOLPETAZO
¿Qué es mejor que enviar SSH a la máquina de su esposo / esposa y luego dejar que su NIC haga la parte divertida de flashear el código morse para "Happy Valentines Day" para su lenguaje de scripting favorito? Estoy seguro de que casi todos han comenzado - BASH? Y como todos sabemos Geeks, siempre debe tener en cuenta la NIC de su máquina;)
#!/bin/bash
#.... .- .--. .--. -.-- ...- .- .-.. . -. - .. -. . ... -.. .- -.--
#1111 12 1221 1221 2122 1112 12 1211 1 21 2 11 21 1 111 211 12 2122
while IFS= read -r -n1 char
do
ethtool eth0 p$char
done < morse
Por supuesto, "morse" contiene el código morse "traducido" a números:
111131231221312213212231112312312113132132311321313111321131232122
'1' es corto, '2' es largo y '3' es espacio. Obviamente, debe instalarse el obligatorio 'ethtool'. Si no, entonces su cónyuge el favor de hacerlo.
Mathematica
ContourPlot3D[(2 x^2 + y^2 + z^2 - 1)^3 - (1/10) x^2 z^3 - y^2 z^3 ==
0, {x, -1.5, 1.5}, {y, -1.5, 1.5}, {z, -1.5, 1.5}, Mesh -> None,
ContourStyle -> Opacity[0.8, Red]]
Esa es la superficie del corazón de Taubin . Sí, me doy cuenta de que el desafío requiere el arte ASCII. Sin embargo, si va a votarlo negativamente, no lo haga porque es excesivamente hermoso, hágalo porque robé el código de /math/12098/drawing-heart-in-mathematica
Solo por interés, el recuento de personajes es 865 .
'=~~~~:''=<<'+~>,'+~~~>,':'''=<'+~>,<',<'+~>-~>:''''=<'+~>,<<',~~>+~>+~~:'''''=',',~~:''''''=',<<'+~>,<'+~~>+~>:'''''''=',~~+~~:
@''''':@''':@''':@''':@''':@''''':@''''':@''''':@''':@''':@''':@''':@''''''':
@'''':@''''':@''''':@''''':@''''':@'':@''''':@'''':@''''':@''''':@''''':@''''':@'':@''''''':
@'''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@'''''':@''''''':
@'':@''''':@|I|:@''''':@|<|:@|3|:@''''':@|~|:@|-|:@|~|:@|!|:@''''':@'''':@''''''':
@''''':@'':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@'''':@''''''':
@''''':@''''':@'':@''''':@''''':@''''':@''''':@''''':@''''':@''''':@'''':@''''''':
@''''':@''''':@''''':@'':@''''':@''''':@''''':@''''':@''''':@'''':@''''''':
@''''':@''''':@''''':@''''':@'':@''''':@''''':@''''':@'''':@''''''':
@''''':@''''':@''''':@''''':@''''':@'':@''''':@'''':@''''''':
Salida:
____ ____
/ \ / \
| |
\ I <3 ~-~! /
\ /
\ /
\ /
\ /
\ /
¿Recuerdas cuando las personas no tenían computadoras para San Valentín y tenían que grabar su vida amorosa en los árboles? Eso es lo que estoy haciendo:
def valentine(person1,person2):
leading_whitespace = range(0,4)[::-1] +[0]+range(0,8)
inside = [3,5,14,14]+range(0,15)[::-1][::2]
layers = [" ___ ___",r" / \ / \ ",r'/ \/ \ ','| |']
for i in range(5,12):
layers.append(' ' * leading_whitespace[i] + '\\' + ' ' * inside[i] + '/')
#inserts person1 into layers[4]
temp = []
for char in layers[3]: temp.append(char)
temp[1:len(person1)+1] = person1
layers[3] = ''.join(temp)
temp = []
layers[4] = '| + |'
# do that again for person2
for char in layers[5]: temp.append(char)
temp[-len(person2)-1:-1] = person2
layers[5] = ''.join(temp)
print '\n'.join(layers)
valentine('Me','Python')
Nota: los primeros valores de la inside
variable están codificados. Salida:
___ ___
/ \ / \
/ \/ \
|Me |
| + |
\ Python/
\ /
\ /
\ /
\ /
\/
#include<stdio.h>
#include<conio.h>
main();
{
int i, n;
printf(" enter n=");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf(" i love you honey ");
}
scanf("%d",&i);
getch();
}