Eww, esos bytes son brutos

86

Escriba un programa o función que, cuando se le da una cadena, filtra tantos bytes distintos como sea posible y devuelve la cadena limpia. Sin embargo, dado que su programa los odia, ninguno de estos bytes puede estar presente en su propio código.

Su puntaje será el número de bytes distintos que su programa filtra de la entrada, cuanto mayor sea, mejor. Este es un puntaje máximo de 255 (ya que su programa debe tener un mínimo de un byte). El desempate es la longitud de su código, con menor es mejor.

Por ejemplo, si su programa filtra los bytes 0123456789, recibe una puntuación de 10, pero su programa en sí no puede contener estos bytes.

Reglas

  • Bytes significan octetos.
  • También tiene la opción de tomar la entrada como una lista de enteros, con valores que van de 0 a 255. Estos corresponden a los bytes equivalentes.
    • Su salida debe estar en la misma forma que su entrada
  • No leer su código fuente
  • Tu código no debe estar vacío
  • Sí, sé que habrá una respuesta Lenguage / Unary. Pero al menos golf por favor?;)

Editar regla:

  • Puede elegir ignorar un byte, por ejemplo, si no se puede distinguir del byte de terminación para una cadena o para EOF. Sin embargo, esto significa que no puede usarlo en su envío, ni cuenta para su puntaje. Si elige hacerlo, su puntaje máximo será 254, pero no tiene que manejar ese byte que está en su entrada.
code-challenge  restricted-source  self-referential 
— Jo King
fuente
1
¿Está bien si la función no funciona si la cadena contiene bytes nulos (\ 0)? Como C usa cadenas terminadas en nulo, una función no puede saber si es el final de la cadena o simplemente un byte nulo.
— wastl
44
"Bytes significa bytes octales". ¿Te refieres a los octetos? Octal es una forma de escribir números, tres bits a la vez, por lo que no siempre se alinea con los límites de bytes.
— Kevin
1
parece estar rogando por una respuesta en brainfuck
— Jasen
1
@cmaster Para las personas que no pueden ver las publicaciones eliminadas: hay un par de intentos de ataque mental, ambos fallan porque no pueden distinguir un byte NUL de EOF.
— Ørjan Johansen
3
@ ØrjanJohansen He agregado una regla que puede permitirle ignorar un byte (para fines EOF). Esto no debería ser demasiado abusivo, ya que también disminuye su puntaje máximo y hace que la pregunta sea más inclusiva.
— Jo King

Respuestas:

34

Python 2 , puntaje 249, 1732 bytes

c="%c%%c%%%%c%%%%%%%%c"
ex=c==c
ee=c==""
exec"e=%x%%x"%ex%ex
exec"e%%%%%%%%=%x%%x%%%%x"%ee%ex%ee
exec"ee=%x%%x"%e%ee
exec"ee%%%%=%x%%x"%ex%e
exec"e=%x%%x"%ee%e
exec"ec=ex%cex"%e
exec"xe=ec%cec"%e
exec"xx=xe%cxe"%e
exec"xc=xx%cxx"%e
exec"ce=xc%cxc"%e
exec"cc=ce%cce"%e
exec"eee=xx%cec"%e
exec"cee=ce%cec"%e
exec"exe=ce%cex%%cxe"%e%e
exec"xxe=ce%cxx"%e
exec"cxe=ce%cex%%cxx"%e%e
exec"ece=ce%cec%%cxe%%%%cxx"%e%e%e
exec"xce=ce%cex%%cxe%%%%cxx%%%%%%%%cxc"%e%e%e%e
exec"cce=cc%cex%%cce"%e%e
exec"eex=cc%cex%%cec%%%%cce"%e%e%e
exec"xex=cc%cex%%cxe%%%%cce"%e%e%e
exec"cex=cc%cec%%cxe%%%%cce"%e%e%e
exec"exx=cc%cxx%%cce"%e%e
exec"xxx=cc%cex%%cxx%%%%cce"%e%e%e
exec"cxx=cc%cec%%cxx%%%%cce"%e%e%e
exec"ecx=cc%cxe%%cxx%%%%cce"%e%e%e
exec"xcx=cc%cec%%cxe%%%%cxx%%%%%%%%cce"%e%e%e%e
exec"ccx=cc%cex%%cec%%%%cxe%%%%%%%%cxx%%%%%%%%%%%%%%%%cce"%e%e%e%e%e
exec"eec=cc%cxc%%cce"%e%e
exec"xec=cc%cec%%cxc%%%%cce"%e%e%e
exec"cec=cc%cex%%cec%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"exc=cc%cxe%%cxc%%%%cce"%e%e%e
exec"xxc=cc%cex%%cxe%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"cxc=cc%cec%%cxe%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"ecc=cc%cxx%%cxc%%%%cce"%e%e%e
exec"""x=""
"""
exec"x%c=c%%xex%%ecc%%xex%%eex"%e
exec"x%c=c%%cee%%cee%%ece%%cxx"%e
exec"x%c=c%%ccx%%xxx%%xcx%%xxe"%e
exec"x%c=c%%eex%%exx%%xec%%xxe"%e
exec"x%c=c%%xex%%cxc%%cce%%ecx"%e
exec"x%c=c%%xxe%%eex%%cxe%%cxe"%e
exec"x%c=c%%cex%%ccx%%xec%%ce"%e
exec"x%c=c%%eex%%ce%%xxx%%xcx"%e
exec"x%c=c%%ce%%eex%%ecc%%ece"%e
exec"x%c=c%%cec%%eec%%ecx%%xxx"%e
exec"x%c=c%%exc%%xxe%%cxe%%cxe"%e
cx="""eec
xec
xxx
xcx
exc
cee
cee
ece
cxx
ccx
xxx
xcx
xxe
xex
ce
cex
ccx
xec
ce
xex
ce
xxx
xcx
ce
xxx
xcx
eec
xxc
exc
xxe
cxe
xxx
cex
ce
xex
ce
xxx
xcx
cee
cee
cee
eee
xex
ecc
xex
eex
cee
xce
exe
cee
cee
cee
cxe"""
exec"exec%cx"%ce

Pruébalo en línea!

Elimina todo menos exc%="y líneas nuevas. La generación del código es de xsot . Dudo que esté optimizado, ¡así que hay muchos bytes para guardar aquí!

— Lynn
fuente
26

Haskell, puntaje 249 250, 1088 335 bytes

(!:)((=:):(!=))=(((!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(!):(!):(!):(!):(:):(:):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(:):(=!))!!(=:))(=:)((!:)(!=))
(!:)(=:)=(=:)
(=:)!(!=)=(!=)
(=!)=(!):(=!)

Define una función !:que toma una lista de enteros y filtra todos excepto 10,33,40,41,58,61los códigos ASCII de \n ! ( ) : =.

Pruébalo en línea!

Cómo funciona: Primero cambiemos el nombre de las funciones y parámetros a nombres sanos:

f (x:xs) = (listOfFunctions !! x) x (f xs)                   -- (!:)
f x = x

listOfFunctions = d:d:d:d:d:d:d:d:d:k:d:d ... : infiniteDs   -- inlined
infiniteDs = d : infiniteDs                                  -- (=!)

k      = (:)                                                 -- inlined
d x xs = xs                                                  -- (!)

La idea principal es tener una lista de dos funciones diferentes ( listOfFunctions), una para mantener un elemento ( k) y otra para soltarlo ( d). El elemento actual indexa la lista a partir de la lista de entrada ( x) y la función que selecciona determina si se debe mantener o descartar el elemento. En el índice 0 tenemos d, porque queremos dejar 0s, el primero kestá en el índice 10, porque queremos mantener 10s (nuevas líneas). Ambos ky dtoman dos parámetros: xy el resultado de una llamada recursiva con el resto de la lista ( xs). kantecede xa la llamada recursiva y dsolo devuelve la llamada recursiva.

La lista literal de funciones termina en el índice 61 (char =, el último ken la lista) y es seguida por un número infinito de d. Esto no solo guarda muchos datos explícitos d, sino que también nos impide tener que finalizar una lista finita con la []que se requerirían caracteres adicionales.

Editar: gracias a @ Ørjan Johansen por +1 puntaje y -753 bytes.

— nimi
fuente
1
Al poner las funciones en la lista en lugar de Bools usted puede deshacerse de |por puntuación de 250, 335 bytes . También definió un sinónimo para repeat (!)acortar la lista (drásticamente, ya que |era mucho más grande que el segundo personaje excluido más grande.
— Ørjan Johansen
Ahora que lo pienso, una función para abreviar algunas de esas (!):secuencias largas probablemente también ayudaría.
— Ørjan Johansen
@ ØrjanJohansen: sí, pero una sublista debe ser finita, por lo que necesita una forma de construir la lista vacía solo con !():=. Extraer []de una lista existente, por ejemplo, la lista de entrada, no funcionará porque tiene tipo [Int], pero necesitamos [a->[a]->[a]].
— nimi
¿Podría explicar cómo funciona? !es curry snd, y =!es una lista infinita de estos, pero eso es todo lo que puedo entender de esto.
— Michail
1
@nimi Me refería a una función además de (=!)algo como (!=)(=:)=(!):(!):(!):(!):(!):(=:)o (más alto nivel, se puede pasar ((!):)o una sección de sí mismo) (!)!=(=:)=(!)((!)((!)((!)(=:)))). Muchas opciones para ajustar. Número de repeticiones, qué tipo de segundo (o incluso tercer) argumento, si lo hay, e incluso si es más óptimo para usar la compresión \no ;(longitudes de bloque 10 22 6 16 2vs. 33 6 16 1).
— Ørjan Johansen
20

JavaScript (ES6), puntuación: 242 (142 bytes)

Un enfoque bastante ingenuo que utiliza una matriz de bytes para E / S.

t=>t.filter(t=>'f'>'fffffffffffffffffffffffffffffffffffffffeeeffffeffffffffffffffeeffffffffffffffffffffffffffffefefffffffeeffeffefffffefe'[t])

Pruébalo en línea!

¿Cómo?

Los 14 caracteres que no se filtran son '().=>[]efilrt. Están marcados con un een la cadena de búsqueda. Para los caracteres anteriores t(código ASCII 116) que no están definidos en esta cadena, 'f'>undefinedes falso .

— Arnauld
fuente
14
Esperaba que uno de estos tuviera exactamente 144 bytes de longitud. Esto merece crédito extra por ser una solución bruta .
— Jeff Bowman,
La descripción dice "cuando se le da una cadena" ...
— Yair Rand
2
@YairRand Y también dice "también tienes la opción de tomar datos como una lista de enteros".
— Arnauld
1
Creo que esta solución es al revés: parece que, idealmente, los únicos caracteres que deberían aparecer son los caracteres realmente utilizados en el código, mientras que todo lo demás se filtra. La buena noticia es que esta solución puede adoptarse rápidamente a trabajar de esa manera, mientras se afeita dos bytes fuera: t=>t.filter(t=>'f'>'fffffffffffffffffffffffffffffffffffffffeeeffffeffffffffffffffeeffffffffffffffffffffffffffffefefffffffeeffeffefffffefe'[t]). Aquí hay una declaración de prueba TIO:console.log(f([...Array(256).keys()]).map(c => String.fromCharCode(c)))
— Scott Hamper
2
@Arnauld Creo que has asustado a todos los otros concursantes decentes de JS con tus veloces supergolf ...
14

Shell POSIX , puntuación 249, 18 bytes

tr -cd \\\\\ cdrt-

Pruébalo en línea!

trComando simple que elimina todos los caracteres pero -\cdrty el espacio. Se necesitan cuatro barras invertidas porque tanto el shell como el trcomando usan escapes de barra invertida. La quinta barra diagonal inversa escapa al siguiente carácter de espacio.

Si tr -cdse considerara un lenguaje de programación, se podría escribir un solo programa de bytes con una puntuación de 255.

— nwellnhof
fuente
Es, creo. Tiene expresiones regulares, que son bastante poderosas.
— wizzwizz4
2
@ wizzwizz4 trtiene clases de caracteres tal como se usan en expresiones regulares, pero no tienen expresiones regulares completas.
— Trauma digital
No entiendo para qué son las barras invertidas aquí. Creo que funcionaría bien sin ellos?
— David Conrad
1
@DavidConrad Lo hace, pero luego no conserva espacios. Entonces necesitas las 4 barras invertidas para una barra invertida.
— wizzwizz4
3
Me afeité un byte, a expensas del cumplimiento de POSIX, con ¡ tr -cd \ cdrt\\-\ Pruébelo en línea!
— wizzwizz4
14

C (gcc) , puntaje 232 235 239 241 242, 260 407 352 249 243 249 bytes

fn(int*f,int*i,int*n,int**t){if(f==i)if(*t=n){}if((f==i)==('+'=='*')){if((*f==',')+(*f=='\'')+(*f=='(')+(*f==')')+(*f=='*')+(*f=='+')+(*f=='=')+(*f=='\\')+(*f=='f')+(*f=='i')+(*f=='n')+(*f=='t')+(*f=='{')+(*f=='}'))if(*n++=*f){}if(fn(++f,i,n,t)){}}}

Pruébalo en línea!

Una función que lleva un puntero al principio y al final de una matriz int (donde end es el primer carácter no incluido), un puntero a un búfer y un puntero a otro puntero int. Escribe el resultado en el búfer y el puntero final del resultado en el último puntero.

— wastl
fuente
1
En caso de que lo ayude, el desafío se ha editado para que ahora se le permita ignorar un valor de byte en particular, por ejemplo, para cadenas terminadas en NUL. Sin embargo, reduce la puntuación.
— Ørjan Johansen
12

Jelly , puntaje 254 (4 bytes)

f⁾f⁾

Pruébalo en línea!

⁾xy es la abreviatura de “xy”(una cadena de dos caracteres).

Nos fIlter la cadena de entrada hasta sólo los caracteres que ocurren en “f⁾”.

— Lynn
fuente
2
Heh, tenía una respuesta preparada, f⁾⁾fpero decidí hacer la pregunta sobre tomar cadenas Unicode antes de publicar.
— Jonathan Allan
10

Ruby -p, puntaje 248 (8 bytes únicos / 483 bytes)

eval""<<11+11+11+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1<<11+11+11+11+1+1<<111+1+1+1+1+1<<111+1+1+1<<11+11+11<<11+11+11+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1<<111+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<11+11+11+11+1+1+1+1+1<<11+11+11+1<<11+11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+1+1+1+1+1<<11+11+11+1+1+1+1+1+1<<11+11+11+11<<11+11+11+1+1+1+1+1+1<<11+11+11+1+1+1+1+1+1

Pruébalo en línea!

— GB
fuente
2
Eso es genial :)
— David Ljung Madison Stellar
10

Python 2 , Score 244 245 246, 13390 1575 bytes

Toma una lista de enteros

exec'%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c'%(111+1,111+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1,11+11+11+11+11+11+11+11+11+11+1,111+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,111+1,111+1+1+1+1+1+1,111+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1,111+1,11+11+11+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+11+1,111+1+1+1,11+11+11+11+11+11+11+11+11+1,11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1,11+11+11+11+11+11+11+11+11+1+1,111+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1,11+11+11+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1)

Pruébalo en línea!

Esto evalúa la siguiente línea de código:

print[x for x in input()if x in map(ord,"exc'%+()1,")]

∼252

Esta respuesta es obviamente teórica. La estructura es

exec'<2**51 times %>c<2**50 times %>c ... %%c%c'%<112 times -~>0%<114 times -~>0% ... %<41 times -~>0%<93 times -~>0

En teoría esto ejecutaría lo mismo que:

print[x for x in input()if x in map(ord,"exc'%-~0")]

Python 3 , puntaje 240 241, 54 bytes

+1 gracias a Jonathan Allan .

lambda a:[i for i in a if i in b""" ":[]abdfilmnor"""]

Pruébalo en línea!

— ovs
fuente
Puede deshacerse de la necesidad \en su versión de Py 3 usando comillas triples b''' ':[]abdfilmnor'''. En Python 2 podría hacer un programa completo en la misma línea para 242: print(''.join(p for p in input() if p in ''' '().fijnoprtu'''))aunque no tan bueno como elexec .
— Jonathan Allan
10

Limpiar , puntuación 247, 234 213 208 bytes

-5 bytes gracias a Ørjan Johansen

== =t
t['\'':t]=['\'': ==t]
t['\\':t]=['\\': ==t]
t[':':t]=[':': ==t]
t['[':t]=['[': ==t]
t[']':t]=[']': ==t]
t['t':t]=['t': ==t]
t['=':t]=['=': ==t]
t[' ':t]=[' ': ==t]
t['
':t]=['
': ==t]
t[tt:t]= ==t
t t=t

Pruébalo en línea!

Utiliza una función recursiva de coincidencia de patrones para eliminar caracteres. Ni siquiera lo necesita StdEnv.

— Οurous
fuente
2
Esto se puede traducir directamente a una función Haskell con 7 caracteres únicos. Misma puntuación que mi respuesta, pero muchos menos bytes (¡ Pruébelo en línea! ). ¡Agradable!
— nimi
@nimi que puede usar en =\ lugar de ===.
— Ørjan Johansen
Creo que quieres cambiar ty tten la segunda última línea.
— Ørjan Johansen
Se ahorra bytes para cambiar el nombre ==de t, pero manteniendo ==como sinónimo de ella.
— Ørjan Johansen
@ ØrjanJohansen Buena captura, gracias!
— Οurous
7

05AB1E , puntuación: 252 253 (  4  3 distintos bytes utilizados; 8 bytes en total)

„ÃJ„„JJÃ

Pruébalo en línea.

Explicación:

„ÃJ        # Push the String "ÃJ"
   „„J     # Push the string "„J"
      J    # Join them together: "ÃJ„J"
       Ã   # Only keep these three characters from the (implicit) input
           # (and output the result implicitly)

Tenga en cuenta que el orden de ÃJy „Jen las cadenas de 2 caracteres son importantes, ya „que también se utiliza para las palabras del diccionario , donde cada dos caracteres es una palabra del diccionario (a excepción de algunos caracteres seleccionados como letras, dígitos -y demás). Entonces „JÃsería 'una palabra' J, así como una palabra del diccionario Ã+ el siguiente carácter (en este caso „), que aparentemente es la palabra"causing" .

— Kevin Cruijssen
fuente
66
Tachado 4 con espaciado sigue siendo un tachado 4
— Jo King
7

Perl 5, puntaje 251 (5 bytes distintos, 8058 bytes en total)

s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s>><><<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<^>^>^^s>^><>^s<^>^>^^s>^>s>^s>^>e>^s>^>^>^s<^>^>^^s>^><>^s>^><>^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s^^^<<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s>><<><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<^>^>^^s>^><>^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><<><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s>><<><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>><<><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<eee<e^<see><>>>^<^<^>^^^^s^s^s>^<^^^^^^^^^^^>^<^^^>>eeee

Pruébalo en línea!

Utiliza el <>^essubconjunto completo de Turing de Perl . El código anterior se obtuvo mediante la ejecución print<>=~y<<>^es><>cdra través de mi convertidor .

— Mugriento
fuente
7

Brachylog , puntaje 249, 16 bytes

{∈"{∈\\\"&}ˢ"&}ˢ

Pruébalo en línea!

No estoy completamente seguro de cómo funciona esto con las reglas, qué con Brachylog tiene su propia página de códigos especial y todo, pero aún puedo explicar cómo funciona:

{                Start of inline predicate.
 ∈"              Input is a member of the string literal containing:
   {∈            the opening bracket, the member-of character,
     \\\"        backslash, quote,
         &}      ampersand, the closing bracket,
           ˢ"    and the superscript s.
             &}  Unify the input to the inline predicate with the output from the inline predicate.
               ˢ Output everything from the input that made it through the inline predicate.
— Cadena no relacionada
fuente
7

Octava , puntaje 248 249 (50 bytes)

No tenía que haber una manera mejor ... y no hay! 

@(a)a('l'=='a'==all('l'=='a'==(a==('@al()''=')')))

Pruébalo en línea!

Filtra todo menos eso @al()'=. La allfunción es superior any, porque solo usa dos bytes distintos. Tenga en cuenta que any(...)es igual a not(all(not(...))). Entonces, comenzamos con el programa

@(a)a(~all(a~=('@al~()''=')'))

En lugar de ~( not) también podemos escribir 0==. Por supuesto, eso significaría que también tenemos que filtrar 0. En cambio, tenga en cuenta que la siguiente expresión también es falsa (cero)

'l'=='a'

Si la compatibilidad con MATLAB no es un problema, puedo ir a 47 bytes

@(a)a((l='l'=='a')==all(l==(a==('@al()''=')')))
— Sanchises
fuente
7

Lenguage (con stty +brkint -ignbrk), puntuación 255, 3890951 bytes

El programa consta de 3890951 bytes NUL (lo que lo convierte en uno de los programas de Lenguage más cortos de la historia; 3890951 bytes es fácilmente lo suficientemente pequeño como para caber en mi disco, por lo que realmente ejecuté esto en un intérprete de Lenguage). El OP quería que la solución Lenguage / Unary se jugara, así que aquí vamos. (Tenga en cuenta que Unary sería mucho más largo porque requiere 0el uso de NUL en lugar de permitirlo).

Tenga en cuenta que Lenguage, a pesar de lo que implica su documentación, no actúa como Brainfuck; I / O funciona de manera completamente diferente (algo que noté al probar este programa). En particular, Lenguage se niega a recibir información de otra cosa que no sea un terminal, por lo que los bytes que se están filtrando son los bytes sin procesar enviados a través de la conexión del terminal (tenga en cuenta también que al filtrar los bytes sin procesar, no verá el teclas que escriba en absoluto). En la práctica, esto significa que el programa absorberá cualquier tipo de entrada que se le envíe, excepto el byte NUL (típicamente escrito como Ctrl- @), que se repetirá literalmente (en ese punto, la gran mayoría de los terminales lo ignorarán). ya que el byte NUL es el equivalente terminal de una instrucción NOP). Para verificar que el programa funciona, '

¿Qué pasa en EOF? Bueno, si el terminal está enviando una serie de bytes, no hay forma de enviar EOF; Los 256 bytes posibles se interpretan literalmente, y no hay nada más que pueda insertar en la secuencia del terminal. Sin embargo, si está utilizando un terminal en serie antiguo, puede presionar el botón de "interrupción" en su terminal para enviar intencionalmente datos mal codificados, permitiendo un código 257º posible; Este "descanso" es el único equivalente plausible de un EOF, ya que se envía fuera de banda e indica algo más que datos válidos. Si la configuración de su terminal tiene el indicador de "interrupción en pausa" establecido (y el intérprete de Lenguage no, por lo que puedo decir, altera esa configuración), el envío de la señal de interrupción hará que el intérprete de Lenguage se bloquee, que convenientemente actúa como una forma de implementar el comportamiento EOF deseado. No estoy seguro de si esta es una configuración predeterminada (porque en la actualidad nadie usa terminales seriales, básicamente nunca aparece), así que lo mencioné en el encabezado como parte de la especificación del intérprete de idiomas que se utiliza.

Explicación

  1110110101111100000111
001                       Initialise tape element 0 to -1
   110               111  While tape element 0 is nonzero:
      110   111              While tape element 0 is nonzero:
         101                    Read a byte from the terminal into tape element 0
               100           Output tape element 0
                  000        Add 1 to tape element 0

El bucle interno solo saldrá cuando se escriba NUL en la terminal; después de esto, inmediatamente hacemos eco del carácter escrito (es decir, el NUL). Agregar 1 en este punto asegurará que el elemento de cinta 0 vuelva a ser distinto de cero, de modo que el bucle externo no pueda salir (hasta que una entrada de interrupción bloquee el intérprete), y volveremos al bucle interno.

Es más divertido usar la resta para ingresar al bucle externo, pero además de continuar haciendo un bucle alrededor; la adición tiene una codificación más corta, pero no puede aparecer al inicio del programa (ya que la codificación se vería como ceros a la izquierda y, por lo tanto, se ignorará).

— ais523
fuente
Por cierto, estoy bastante seguro de que puedo ejecutar cualquier programa Lenguage <4TB a pesar de no tener un disco tan grande. Al intérprete no le importan los archivos con agujeros.
— Joshua
truncateno está creando archivos dispersos para mí (¿tal vez el sistema de archivos no los admite?). Sin embargo, por lo que puedo decir, el intérprete de Lenguage de referencia lee el archivo de entrada línea por línea (!), Por lo que si el programa no contiene caracteres de nueva línea, un programa suficientemente largo terminará agotando la memoria disponible. Por supuesto, esto podría solucionarse con un nuevo intérprete.
— ais523
No truncar Busque un archivo nuevo en un byte antes del final deseado y escriba un byte nulo.
— Joshua
6

Retina 0.8.2 , 12 bytes, puntuación: 250

[^]n\\\n[^]

Pruébalo en línea! Filtra todos los personajes a excepción de nueva línea, [, \, ], ^y n. Aunque los caracteres [\]^son consecutivos, usar un rango realmente costaría un byte y también reduciría mi puntaje.

— Neil
fuente
6

Japt , puntaje 249, 20 bytes

f"[ fq\"[\\\\\\]]" q

Pruébalo en línea!

— Solo ASCII
fuente
Luis logró encontrar la solución óptima, pero podría mejorar su puntaje con oQ+"+oQ"Qo simplemente, oopero eso es solo una variación de la solución de Luis.
— Shaggy
Jaja, tbh, estaba apurando este y se me acabó el tiempo ayer por la noche, y estoy más corto y se está acercando a la solución de luis: P
— Solo ASCII
4

PHP, puntaje 234, 58 62 bytes

<?=preg_replace("_[^\"$(),;<=?[\]^\_\\\\aceglnpr]_","",$argn);

Ejecutar como tubería con -nFo probarlo en línea .

— Titus
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4

Ruby -paF[^$_=F*'], puntaje 250, 8 bytes

$_=$F*''

No estoy seguro de que esto sea legal según las reglas actuales del sitio para las banderas de línea de comandos, ya que la "bandera" aquí es una especie de código que incluye bytes prohibidos. La Fbandera define una expresión regular de separador de entrada que consiste en todos los caracteres que no están en el código propiamente dicho. El código propiamente dicho establece la salida en la concatenación de todos los registros de entrada.

— histocrat
fuente
4

MATL , Score 252

t't''m)'m)

Pruébalo en línea!

Explicación (para entrada input)

t         % Duplicate input. 
          % Stack: {'input', 'input'}
't''m)~'  % Push the string t'm)~ 
          % Stack: {'input', 'input', 't'm)~'}
m         % 'ismember' to filter
          % Stack: {'input', [0 0 0 0 1]}
)         % Index into input.
          % Stack: {'t'}
          % Implicit display.
— Sanchises
fuente
3

K, puntaje 246, 23 bytes

{x@&~x in"\"~ in@&{x}"}

{..} es una lambda con arg x

leer como 'devuelve x en donde no x en la cadena'

La cadena contiene \ "~ en @ & {x} (los diez bytes utilizados en el programa)

— J. Sendra
fuente
3

sfk , puntaje 239, 133 bytes

+xed -i -case ixixi x+x+x xexex xdxdx x-x-x xixix xcxcx xaxax xsxsx xbxbx xyxyx xtxtx x"x"x x\[x\[x x\]x\]x x\\x\\x "x x x" x[byte]xx

Pruébalo en línea!

Realiza reemplazos en la entrada (escrita como [delim][from][delim][to][delim]) cambiando todos los caracteres utilizados en el programa a sí mismos, lo que elimina las posiciones de los caracteres de la consideración para la entrada al reemplazo final x[byte]xxque asigna todos los bytes a la cadena vacía.

— Οurous
fuente
3

JavaScript, puntaje 250, 95573 59273 bytes

Una solución JS ligeramente desarrollada que luego se ejecuta a través del algoritmo de JSFuck . Muchos bytes, pero una buena puntuación.

Original:

a=t=>t.replace(/[^![\]+()]/g,'')

La representación de JSFuck tiene 59273 caracteres:

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— tschwab
fuente
2
s=>s.replace(/[^![\]+()]/g,'')debería funcionar
— solo ASCII
Sí, lo hizo significativamente. Buena idea. Sin embargo, creo que pase lo que pase, será del orden de miles de bytes.
— tschwab
3

brainfuck , Puntuación: 248, 162 bytes

,[>---[----------->--<]>-[>->->->-->------->-->-------[<<]>-]>--->-->->--->------------->->-----------[<]<<[->>>->->->->->->->-<<<<<<<<<<]>>>[>]>[[>]<[->-<]>.>],]

Pruébalo en línea!

Por lo general, no respondo mis propias preguntas, pero la gente parece haber leído mi página de perfil, especialmente donde dice If someone comments on a question "I wish there was a brainfuck solution", I feel obliged to provide one.

Los bytes filtrados son -<>[],.e ignoran el byte NUL, ya que no se puede distinguir de EOF. Esto es un poco más largo de lo habitual, ya que deliberadamente evito usarlo +para obtener una puntuación ligeramente mejor. Aun así, podría ser capaz de jugar golf en la parte de generación de números para ahorrar unos pocos bytes.

— Jo King
fuente
1
Tanto las presentaciones en C como en Lenguage ya se han adaptado específicamente a la necesidad de distinguir NUL de EOF. ¿Quizás usar un BF de 16 bits con una convención EOF diferente?
— Ørjan Johansen
3

Espacio en blanco , puntuación: 253 (3 bytes distintos utilizados, 97 bytes en total)

[N
S S N
_Create_Label_LOOP][S S S N
_Push_0][S N
S _Duplicate_0][T   N
T   S _Read_STDIN_as_character][T   T   T   _Retrieve][S N
S _Duplicate_input][S S S T S S T   N
_Push_9][T  S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][S N
S _Duplicate_input][S S S T S T S N
_Push_10][T S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][S N
S _Duplicate_input][S S S T S S S S S N
_Push_32][T S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][N
S N
N
_Jump_to_Label_LOOP][N
S S S N
_Create_Label_PRINT][T  N
S S _Print_character][N
S N
N
_Jump_to_Label_LOOP]

Se agregaron letras S(espacio), T(tabulación) y N(nueva línea) solo como resaltado.
[..._some_action]agregado solo como explicación.

Pruébelo en línea (solo con espacios en bruto, pestañas y nuevas líneas). Una buena ventaja es que puedo usar este código para transformar el código resaltado arriba en el programa de espacio en blanco sin procesar (que hice en este TIO como ejemplo), para el cual generalmente uso Notepad ++. :)

Explicación:

Muy claro. Aquí el pseudocódigo:

Loop indefinitely:
  Character c = STDIN as character
  if(c == SPACE or c == TAB or c == NEWLINE):
    Print c as character
  Go to the next iteration of the loop
— Kevin Cruijssen
fuente
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