Cuadrado y cuadrado [cerrado]

8

Los cuadrados se ven simétricos, y también lo son los códigos requeridos.

Objetivo : escribir un programa cuyo código fuente sea un cuadrado sólido (N líneas con N caracteres imprimibles que no sean espacios en blanco en cada línea) e imprime un cuadrado de igual tamaño. Un programa (o salida) con ancho y alto inconsistentes no es válido. (por ejemplo, 6x5)

Ejemplo (HQ9 +)

QAA
AAA
AAA

Requisitos

  • Tanto la fuente como la salida deben contener N líneas y N caracteres imprimibles en cada línea, seguidos de 1 salto de línea. Su programa no debe contener ni mostrar caracteres de control (excepto LF o CR-LF) o espacios en blanco (Espacio, Tabulador, VTab)
  • Las lagunas estándar son aburridas, no las use.
  • Un programa (y salida) con un solo carácter es básicamente nada. N debe ser al menos dos.
  • El contenido de la salida no importa, siempre que cumpla con la regla 1
  • Regla especial : no use comentarios o códigos que no afecten la salida para "llenar" su código.
    Para ser claros, se le permite usar en i++;i++;... i++;lugar de i+=10;, pero no debe definir una variable string s="placeholder"pero nunca usarla más tarde. Es muy fácil evitar esta regla, así que no seas demasiado estricto.
  • Si desea generar una nueva línea antes que todo lo demás, está bien, pero declare que está utilizando esta regla.
    Si desea generar la última línea sin un salto de línea posterior, también está bien y no necesita declararla. Sin embargo, eso no afecta la puntuación.

Adicional : Indique el número N (ancho / alto) que usa su programa. Proporcione descripciones de su código si es posible.

No es necesario indicar la longitud (en bytes) de su programa porque la N lo dice todo.

Como se trata de un juego de bolos de código , ganará el programa con la N más grande y la mayor complejidad.

source-layout  printable-ascii  code-bowling 
— iBug
fuente
66
¿Cuál es el tipo de este desafío (por ejemplo, código de golf, concurso de popularidad)?
— Jakob
44
No creo que esto esté a la altura de nuestros estándares de concursos de popularidad. Simplemente golpear la etiqueta en una pregunta no es suficiente. Lea el wiki de etiquetas para obtener una guía más detallada.
— Ad Hoc Garf Hunter
3
También debe definir qué se entiende por comentario. Este no es un término definido por sí solo.
— Ad Hoc Garf Hunter
44
Hemos tenido desafíos similares antes. Sugeriría hacer este código de golf, tal vez agregando etiquetas de fuente restringida o quine, y tal vez eliminando el requisito de no hacer comentarios, ya que no está claro. No vería ninguna razón para no volver a abrir entonces.
— m-chrzan
55
@iBug esto tenía la etiqueta de código de golf durante unas buenas 7 horas antes de ser cambiado a exactamente lo contrario: código de tazón. La mayoría de las respuestas están tratando de encontrar el cuadrado mínimo que genera un cuadrado. Además, con las limitaciones dadas, es muy fácil crear cuadrados arbitrariamente grandes en la mayoría de los idiomas. Agregar limitaciones sería una vez más injusto para las respuestas actuales.
— m-chrzan

Respuestas:

21

JavaScript (ES6), N = 5

Con una nueva línea inicial en lugar de una nueva línea final.

alert
((a=`
`+!!0
)+a+a
+a+a)
Expandir fragmento

JavaScript (ES6), N = 6

alert(
(1e5+`
`)['r'
+'epe\
'+'at\
'](6))
Expandir fragmento

JavaScript, N = 7

this['\
consol\
e'].log
('1234\
567\n'[
'repea\
t'](7))
Expandir fragmento

JavaScript, N = 202

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]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!
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+(!![]+[])[!+[]+!+[]+!+[]])()(([]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+
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+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]+(!!
[]+[])[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(+(!+[]+!+[]+[+!+[]]+[+!+[]]))[(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![
]+[])[+!+[]]])[+!+[]+[+[]]]+(+![]+([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[
])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[
]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]
+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([![]]+[][[]])[+
!+[]+[+[]]]+([][[]]+[])[+!+[]]+(+![]+[![]]+([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+
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+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]
+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]](!+[]+!+[]+!+[]+[+!+[]])[+!+[]]+(!!
[]+[])[!+[]+!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]+(![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+[
!+[]+!+[]]+[+[]]+[+[]]+(+(+!+[]+(!+[]+[])[!+[]+!+[]+!+[]]+[+!+[]]+[+[]]+[+[]])+[])[!+[]+!+[]]+[!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[
!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]])()
Expandir fragmento

— Darrylyeo
fuente
Aquí está para N = 4(no estoy seguro si la nueva línea al principio está permitida).
Tengo una solución para N = 5 pastebin.com/9NFjBbxT
— kamoroso94
Aquí hay una solución para N = 4 sin una nueva línea líder en la salida pastebin.com/pGvBQ1VK
— kamoroso94
Esa solución N = 6 no es válida porque solo hay 5 líneas.
— iBug
Creo que lo que he dicho es un cuadrado , no un rectángulo .
— iBug
8

Perl 5, 5 × 5

print
q.u.x
$],$/
for(t
..x);

Esto está ligeramente ofuscado para hacerlo más interesante, así que aquí hay una explicación: q.u. es lo mismo que'u' . El siguiente xes el operador de repetición , por lo que 'u'se repite $]veces. $]está entre 5 y 6 , por lo que 'u'se repite 5 veces. Luego agrega la nueva línea$/ y printtodo. Todo esto se hace una vez para cada miembro de la lista t..x: ty xcomo palabras vacías se asignan los valores 't'y 'x'respectivamente, y la lista es así't','u','v','w','x' . Entonces la salida es:

uuuuu
uuuuu
uuuuu
uuuuu
uuuuu
— msh210
fuente
1
Su explicación completa merece un voto a favor.
— iBug
8

Rubí, 3x3

!p\
p,\
p,p

Huellas dactilares

nil
nil
nil

Pruébalo en línea!

Cómo funciona

pes un método que imprime cada uno de sus argumentos, luego devuelve el valor (o una matriz de los valores) que imprimió. Si se llama sin argumento, no imprime nada y regresa nil. Así, las ps de las líneas 2 y 3 se evalúan todas nil, y la primera pimprime esas nils.

— m-chrzan
fuente
7

Carbón , n = 2

Solución aburrida (el carbón simplemente imprime ASCII literalmente):

sq
re

Pruébalo en línea!

— Solo ASCII
fuente
1
¿Significaría que podría hacer que el programa sea arbitrariamente grande, ya que solo se imprimiría solo?
— Brian J
Sí (texto de relleno aleatorio para hacer este comentario de más de 15 caracteres)
— solo ASCII el
1
Lo mismo puede decirse de php si el archivo no comienza con <?/ <?php.
— Alok
7

C, N = 7

i;main(
){for(i
=01;i<=
56;i++)
putchar
(i%8?37
:012);}

Imprime una cuadrícula de 7x7 de %, es decir

%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
— iBug
fuente
5

brainfuck , 9x9

++[->+++<
]>+++[->+
>+<<]<--[
>+<++++++
]><<++[->
+++++<]>>
>>[<[-<.>
]<<.>>+++
++++++>-]

Pruébalo en línea!

Produce un cuadrado de +(la función más fundamental de brainfuck).

Volveré cuando descubra cómo convertir esto en una quine, tan duras 3 semanas más o menos ...

— Graviton
fuente
Todavía no he descubierto la manera de quine esto.
— Graviton el
Nada ha cambiado
— Graviton
4

Haskell, 7x7 6x6

f=b>>y
y=b++n
n="\n"
b=c++d
c=d++d
d="--"

Salidas

------
------
------
------
------
------

Pruébalo en línea!

Cómo funciona:

f=             -- main function which returns the string
  b>>y         --   length b copies of y, i.e. 6 times y, because: 

d="--"         -- basic building block of the string
c=d++d         -- c -> "----"
b=c++d         -- b -> "------" -> b has length 6
y=b++n         -- y -> 6 dashes plus newline "-------\n"

Con los indicadores del compilador permitidos, hay una solución 5x5:

Haskell, 5x5 (con el indicador del compilador -cpp)

(>>)\
[1,2\
..5]\
"abc\
de\n"

Pruébalo en línea!

-cppinvoca el preprocesador cpp que permite el plegado de línea a través de \.

— nimi
fuente
¿Qué pasó con el 7x7? Parece estar bien, pero no estoy familiarizado con Haskell.
— Solomon Ucko
@SolomonUcko: Aunque el OP dice que el cuadrado más grande gana, todos trataron de ser lo más pequeños posible, porque es trivial hacer cuadrados enormes al completar cosas innecesarias (incluso dentro de las reglas del desafío). Después de mi 7x7 encontré una solución 6x6, así que actualicé mi respuesta.
— nimi
Ok, eso tiene sentido. ¿Supongo que podrías publicar ambos?
— Solomon Ucko
@SolomonUcko: claro, pero el 7x7 es básicamente el mismo que el 6x6, por lo que no es muy interesante.
— nimi
Cierto. Parece que el cambio es principalmente cambiar nombres de variables, eliminar puntos y comas y eliminar una declaración de asignación innecesaria.
— Solomon Ucko
3

SOGL V0.12 , N = 3 2

H$
$Q

Pruébalo aquí!

La primera línea - H$significa in the continuing lines replace $ with H, resultando en la siguiente línea HQ. Eso luego se ejecuta:

H   decrease POP (nothing on the stack so input (no input so 0)) - results in 0-1 = -1
 Q  output that without popping
    implicitly output POP as none of `tTpP` were called

Encontré esto mediante la fuerza bruta a través de todos los programas en longitud 2 (ya que cualquier programa como ..\n..siempre se reducirá a un programa de 2 caracteres)

— dzaima
fuente
3

Pitón 2 , n = 6

print\
'\n'.\
join(\
['###\
###']\
*+~-7)

Pruébalo en línea!

No tan golfizado como podría ser, pero ... tengo que llenar los vacíos de alguna manera, ¿no?

— Solo ASCII
fuente
No creo que esto pueda ser más golfizado ... porque en printsí mismo tiene 6 bytes y 1 byte '\' es la compulsión más baja.
— officialaimm
Sí, quise decir que se puede jugar a ~ 16 bytes si no hubiera restricciones de formato de origen
— solo ASCII
1
@officialaimm bien técnicamente podrías construir la cadena "print"y luego eval, pero creo que irás demasiado lejos para caber en un 5x5...
— Stephen
@StepHen oh sí ... eval podría ser un remedio ...
— officialaimm
3

Rubí , n = 6 5

Guardado 12 bytes gracias a m-chrzan

puts(
"Rub\
y!\n\
"*(1+
2+2))

Pruébalo en línea!

Sí, tengo la intención de Leaky Nun este EDITAR:: / las restricciones de fuente son peores de lo que pensaba para la mayoría de esolangs, y los idiomas normales también

— Solo ASCII
fuente
5x5 con puts.
— m-chrzan
3

> <> , N = 3

"vn
:/^
ao/

Se imprime

110
110
118

¡Pruébelo en línea o mírelo en el área de juegos para peces !

Esto es un poco complicado, así que tengan paciencia conmigo. El pez comienza en la esquina superior izquierda e inmediatamente entra en modo cadena. Empuja los códigos de caracteres de "v" y "n" a la pila, que son 118 y 110 respectivamente. El pez luego se envuelve y golpea "nuevamente, saliendo del modo de cuerda. El venvía entonces los peces hacia abajo, y la /refleja a la izquierda en :, lo que duplica la parte superior de la pila: la pila es ahora 118, 110, 110.

El pez luego se envuelve y lo ^envía en un bucle:

  n
  ^
ao/

Este bucle imprime la parte superior de la pila como un número ( n), se ajusta y rebota, empuja a = 10 = salto de línea a la pila, luego lo imprime como un carácter ( o) y comienza el bucle nuevamente. Cuando la pila está vacía, nprovoca un error y el programa se detiene.

Se ha señalado en los comentarios que detenerse con un error es bastante insatisfactorio. Por lo tanto, te doy una alternativa que se detiene naturalmente, en un cuadrado de 4x4:

aa|v
no"/
lo~/
;!?/

Se imprime

/110
/110
/110
/110

Pruébalo en línea!

— No un arbol
fuente
La impresión something smells fishy...no cuenta, ya que técnicamente se imprime cuando el programa falla (IIRC se imprime en STDOUT).
— cole
@cole, estoy bastante seguro de que se imprime en STDERR, que se ignora por defecto . Parar con un error es una forma muy común de detener>> programas. Sin embargo, si realmente desea un código sin errores, puedo colocarlo en un cuadrado de 5x5: ¡ Pruébelo en línea!
— No es un árbol
1
Debo estar olvidando mi> <>. Por cierto, me gustan ambas soluciones (y creo que el 3x3 es especialmente inteligente).
— cole
2

CJam, n = ∞

Versión raíz: n = 2

AN
BN

Pruébalo en línea

Huellas dactilares

10
11

Se puede extender a cualquier n anteponiendo números a cada línea. P.ej:

n = 11

123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN

Huellas dactilares

12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910

Pruébalo en línea

— geokavel
fuente
1

Perl 5 , 4x4

(say
1111
)for
1..4

Pruébalo en línea!

Requiere -M5.010en la línea de comando.

— m-chrzan
fuente
Por cierto, ¿cmdlinearg -M5.010tiene el mismo efecto que una línea en el archivo que lee use 5.010;?
— iBug
@iBug generalmente use 5.010o -M5.010puede considerarse como gratuito, ya que se puede acceder a la mayoría de las características importadas mediante la ejecución de la secuencia de comandos a través perl -Ede la perl -ecual tiene la misma longitud.
— Dom Hastings
1
No piense que hay una longitud 3 var (no es que pueda ver de perlvartodos modos) de lo contrario podría obtener un 3x3 con algo como esto ... ¡ Pero jugaré con esto hoy!
— Dom Hastings
1

cerebro , N = 6

++++++
++++>-
--->++
++++[<
......
<.>>-]

Podría decirse que esto no es válido ya que elegí arbitrariamente el carácter de salida para que sea 3 puntos de código más bajo para arreglar el cuadrado ...

Pruébalo en línea!

— Dom Hastings
fuente
1

Python 3 , N = 13 (181 bytes)

print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)

Pruébalo en línea!

No veo por qué esto no sería válido, ya que no hay una regla que me obligue a no usar esta técnica (creo). Esto imprime una cuadrícula de octothorpes 13x13.

— Sr. Xcoder
fuente
1

Aceto , 3x3

Convierta el cero implícito en un flotante ( 0.0), duplicar, imprimir, nueva línea, duplicar, imprimir, nueva línea, imprimir, nueva línea.

dpn
npp
fdn

Versión anterior que puede no ser válida:

Aceto está hecho para este tipo de desafío; Todos los programas son cuadrados, al menos internamente. Puede o no ser válido, ya que en la salida la línea final no termina con un salto de línea. Simplemente calculamos 2 ^ 7, activamos el modo fijo e imprimimos tres veces con nuevas líneas intermedias.

pnp
kFn
27p
— L3viatán
fuente
1

Gaia , 3 x 3

3/ṣ
ṙ×↑
9:⇈

Pruébalo en línea!

Explicación

9    Push 9
 :   Copy it
  ⇈  Call the function above
ṙ    String representation of 9
 ×   Repeated 9 times
  ↑  Call the function above
3/   Split into chunks of 3
  ṣ  Join with newlines

Gaia, 2 x 2

gp
Ø↑

No estoy seguro de si esto es válido ya que es una trampa engañosa ( Øglee el archivo fuente del programa).

— Gato de negocios
fuente
1

PHP, n = ∞

No sé si esto es un vacío legal, pero aquí está la 2versión:

aa
aa

Huellas dactilares

aa
aa

Pruébalo en línea!

Con n = 10

aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa

Pruébalo en línea!

Se puede extender a cualquier número.

— LP154
fuente
55
(No creo que sea una escapatoria, creo que es un ejemplo de por qué no hacemos bolos de código).
— Urna de pulpo mágico
1

TI-BASIC, N = 2

Disp Xmax
Disp Xmax

Tenga en cuenta que Disp(incluido el espacio) y Xmaxson cada uno de los personajes. Como Xmax es 10 por defecto, la salida es:

10
10
— Khuldraeseth na'Barya
fuente
0

Excel VBA, n = 15

Subrutina declarada que toma una variable de entrada vacía (para salida) y salidas a rango [A1], a través de un cuadro de mensaje y a la ventana inmediata de VBE, y a través de la variable de entrada

Sub$A(n):s="1|"
s=s+"2"+"|"+"3"
s=s+"|"+"4"+"|"
s=s+"5"+"|"+"6"
s=s+"7|8|9|0|1"
s=s+"2|3|4"+"|"
s=s+Chr(51+9-7)
tu=Split(s,"|")
var=Join(tu,"")
[B1]=var+vbCrLf
o=[Rept(B1,15)]
MsgBox$o,0,"hi"
Let[A1]=CStr(o)
Debug.Print[A1]
n=o:End:End$Sub

Los autoformatos anteriores para 

Sub A(n): s = "1|"
s = s + "2" + "|" + "3"
s = s + "|" + "4" + "|"
s = s + "5" + "|" + "6"
s = s + "7|8|9|0|1"
s = s + "2|3|4" + "|"
s = s + Chr(51 + 9 - 7)
tu = Split(s, "|")
Var = Join(tu, "")
[B1] = Var + vbCrLf
o = [Rept(B1,15)]
MsgBox$ o, 0, "hi"
Let [A1] = CStr(o)
Debug.Print [A1]
n = o: End: End Sub

y salidas 

123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
— Taylor Scott
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0

Encantamientos rúnicos , n = ∞ (mínimo 7x7)

"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
k@."0<Ra

Pruébalo en línea!

Aprovecha en gran medida la capacidad de Runic para manejar múltiples punteros de instrucción simultáneamente. ¿Qué se duplicó una quine? Por qué, una quine el doble de tiempo.

Todos los .comandos son cómo la expresión de quine básica "'<~S@|se puede expandir para tener un ancho arbitrario. Copias adicionales de la quine expanden el cuadrado verticalmente. Las líneas nuevas y la salida son manejadas por la última línea, canalizando todas las IP de quine a una sola expresión de terminación, que sigue Rak@, que empuja un carácter de nueva línea, luego volca toda la pila de arriba hacia abajo para la salida. La última línea en sí también produce una línea de salida .@kaR<00para mantener el tamaño de estructura requerido. Como la última línea sale primero, no hay una nueva línea inicial o final.

Hay quines más cortos (a saber '<~@|"), sin embargo, la última línea está limitada a 7 caracteres, o no puede producir la salida del ancho correcto ( @"<Raktiene 6 caracteres de longitud, pero solo genera 5 caracteres).

También intenté codificar el cuadrado más pequeño posible. Esto fue lo mejor que pude hacer.

Encantamientos rúnicos , n = 6

\>1CYS
\:$1Xk
\:$S:$
\S:$S:
\$S:$S
\:$q:@

Pruébalo en línea!

Clona repetidamente la parte superior de la pila, la imprime y cambia los dos elementos superiores para imprimir 100000seis veces con 5 líneas nuevas entrelazadas.

Y luego, porque pude:

Encantamientos rúnicos , n = 9

\>311+6Xk
\w421+akw
\"'{~Sak"
\"@|."'"S
\q:1K1K1K
\1K1K1K1K
\1K1K1KE:
\E:E:E:1K
\311++*E;

Pruébalo en línea!

Programa cuadrado de 9x9 que genera una línea cuadrada de 9x9 (con nueva línea inicial).

Esto se logra creando el quine de 9 bytes como una cadena y luego Evalándolo 4 veces, luego multiplicando la cadena por 5 ( "abc"*3-> "abcabcabc") y evaluando una vez más para las últimas 5 copias. Esto se hace de esta manera para llenar el cuadrado de 9x9 hasta el borde.

— Draco18s ya no confía en SE
fuente
0

Wolfram Language (Mathematica) , n = 5

Do[1+
Echo[
+100*
+100]
,5*1]

Salidas

>> 10000
>> 10000
>> 10000
>> 10000
>> 10000

Suponga que no cuenta >>que sería más corto porque solo la función de impresión es Printy Echo. También debe poner al menos 1 carácter después de la función para llamarlo.

Map[1+
Print@
#+10&,
Array[
9^6+1+
#&,6]]

Pruébalo en línea!

Salidas

531443
531444
531445
531446
531447
531448

con una nueva línea al final

n = 7

Print/@
Array[0
+0+0+0+
0+0+0+0
+0+0+0+
1234557
+10&,7]

Pruébalo en línea!

Salidas 

1234567
1234567
1234567
1234567
1234567
1234567
1234567

con una nueva línea al final

— cangrejo de mantequilla
fuente
0

Perl 5, 9x9

for(1..$=
/7){$qq=(
$q=$_)**7
;for($qq%
7..$q/7){
map{print
qq,qqq,,,
qq,qqqqqq
,,}0..2}}

Explicación

El forbucle externo está sobre la secuencia 1 .. ($= / 7). $ = es 60, por lo que el ciclo se ejecuta desde 1 hasta el piso de 60/7, que es 8.

La primera instrucción en el bucle externo $qq = ($q=$_)**7, asigna a la variable $qel valor del índice $_del bucle y asigna $qqel valor $qa la séptima potencia.

Luego viene el bucle interno, que está sobre la secuencia $qq % 7 .. $q / 7( %es módulo).

For this value of $q,      the inner loop is over this sequence:
          1                             1 .. 0
          2                             2 .. 0
          3                             3 .. 0
          4                             4 .. 0
          5                             5 .. 0
          6                             6 .. 0
          7                             0 .. 1
          8                             1 .. 1

Por lo tanto, el bucle interno se ejecuta tres veces en total: dos veces cuando el índice del bucle externo es 7 y una vez cuando el índice del bucle externo es 8.

El bucle interno hace map{...} 0..2otro bucle, esta vez sobre la secuencia 0 .. 2, por lo que hace las siguientes tres veces:

print
qq,qqq,,,
qq,qqqqqq
,,

Los qqs son el operador de comillas dobles , por lo que esto solo imprime qqqy qqqqqq<newline>.

Por lo tanto, la salida es

qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq

Pruébalo en línea.

— msh210
fuente
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